document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433265>Question 433265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Randy invested his inheritance in an account that paid 6.5% interest, compounded continuously. After 7 years, he found that he now had $56,449.07. What was the original amount of his inheritance? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300376 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If its' compounded continuously, then the formula is:<BR>\n" );
document.write( "A=Pe^(rt),where P is your starting amount, r is the rate, and t is the time.<BR>\n" );
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document.write( "A=Pe^(rt)<BR>\n" );
document.write( "A/e^(rt)=P<BR>\n" );
document.write( "56449.07/2.7183^(7*.065)=P<BR>\n" );
document.write( "56449.07/1.5762=\"<BR>\n" );
document.write( "\"\"\"\"\"\"\"=35813.89<BR>\n" );
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document.write( "Randy's inheritance was originally worth $35813.89.<BR>\n" );
document.write( " </SPAN>\n" );
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