document.write( "Question 433290: a) Solve for 5x^2=15
\n" ); document.write( "b) Find the x-intercepts of f(x)=5x^2-15\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #300371 by katealdridge(100) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5x%5E2=15\"$ First, divide both sides by 5.
\n" ); document.write( " $\"x%5E2=3\"$ Then take the sqrt of both sides.
\n" ); document.write( " $\"x=sqrt%283%29\"$ and $\"x=-sqrt%283%29\"$ Don't forget every time you take a square root in a quadratic equation you always get plus and minus the answer.
\n" ); document.write( "The x-intercepts:to find an x-intercept you always substitute 0 in for y in the function.
\n" ); document.write( " $\"0=5x%5E2-15\"$ As you'll see, you get the same answer as you just got above.
\n" ); document.write( "The point is that solving an equation is the same as finding the function's x-intercepts. \n" ); document.write( "

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