document.write( "Question 433317: Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
\n" ); document.write( "point (0, -6).\r
\n" ); document.write( "\n" ); document.write( "A) y =13x + 6
\n" ); document.write( "B) y = -13x - 6
\n" ); document.write( "C) y = -3x - 6
\n" ); document.write( "D) y =13x - 6
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Algebra.Com's Answer #300363 by stanbon(75887)\"\" \"About 
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Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
\n" ); document.write( "point (0, -6).
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\n" ); document.write( "The listed equation has slope = -3,
\n" ); document.write( "so the perpendicular line must have
\n" ); document.write( "slope 1/3
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\n" ); document.write( "Form: y = mx+b
\n" ); document.write( "-6 = (1/3)*0+b
\n" ); document.write( "b = -6
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "y = (1/3)x-6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "Sorry the slections are as follows:
\n" ); document.write( "A) y=1/3x+6
\n" ); document.write( "B)y=-1/3x-6
\n" ); document.write( "C)y=-3x-6
\n" ); document.write( "D)y=1/3x-6
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