document.write( "Question 433312: verify idenity
\n" ); document.write( "csc x = (sin x)/2(1 + cosx) + (sin x)/2(1-cosx)\r
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Algebra.Com's Answer #300362 by katealdridge(100)\"\" \"About 
You can put this solution on YOUR website!
\"sinx%2F%282%281%2Bcosx%29%29%2Bsinx%2F%282%281-cosx%29%29=cscx\"
\n" ); document.write( "Multiplying by the conjugate is sometimes a good way to start.
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\n" ); document.write( "\"%282sin%28x%29%2B2sin%28x%29%29%2F%284-4cos%5E2%28x%29%29=cscx\"
\n" ); document.write( "\"%284sin%28x%29%29%2F%284-4cos%5E2%28x%29%29=cscx\"
\n" ); document.write( "\"%284sin%28x%29%29%2F%284%281-cos%5E2%28x%29%29%29=cscx\"
\n" ); document.write( "\"%28sin%28x%29%29%2F%281-cos%5E2%28x%29%29=cscx\"
\n" ); document.write( "\"%28sin%28x%29%29%2F%28sin%5E2%28x%29%29=cscx\"
\n" ); document.write( "\"1%2F%28sin%28x%29%29=cscx\"
\n" ); document.write( "\"cscx=cscx\"
\n" ); document.write( "That was the hardest thing I ever had to type on here. I hope you understand it!
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