document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433268>Question 433268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log3(x-2) = 1+log3(x-4)    The logs have a base of 3. How do I solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300348 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3(x-2) = log3(3) + log3(x-4)\r<BR>\n" );
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document.write( "x-2 = 3(x-4)\r<BR>\n" );
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document.write( "x-2 = 3x - 12\r<BR>\n" );
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document.write( "10 = 2x </SPAN>\n" );
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