document.write( "Question 45227: !x!_> 3 \n" ); document.write( "
Algebra.Com's Answer #30034 by rapaljer(4671)\"\" \"About 
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\"abs%28x%29+%3E=3\" \r
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\n" ); document.write( "\n" ); document.write( "Do you understand that absolute value of a positive number is positive, the absolute value of 0 is zero, and the absolute value of a negative number is actually the positive number associated with it. Like absolute value of 3 is 3, absolute value of -3 is 3, absolute value of -5 is 5, etc. Be sure you understand this first.\r
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\n" ); document.write( "\n" ); document.write( "Now, draw a numberline, and by trial and error try to find the numbers on the numberline where the absolute value of the number will result in a number that is greater than or equal to 3.\r
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\n" ); document.write( "\n" ); document.write( "Trial and error results in all numbers that are from 3 on the numberline, and to the right on the numberline, like 4, 5, 6, etc.\r
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\n" ); document.write( "\n" ); document.write( "Also, trial and error results in the number -3, and all numbers to the left of -3, like -4, -5, -6, etc. \r
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\n" ); document.write( "\n" ); document.write( "This means that \"x%3E=-3+or+x%3C=+-3\". In interval notation, this would be\r
\n" ); document.write( "\n" ); document.write( "(-inf, -3] U [3, inf).\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "In interval notation
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