document.write( "Question 433233: What is the best way to find factors to reduce a radical? Example: cube root of 81. \n" ); document.write( "
Algebra.Com's Answer #300293 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do a prime factorization.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start with 2. 81 is odd, so 2 is not a factor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Consider 3. The sum of the digits is divisible by 3, so 3 is a factor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "81 divided by 3 is 27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the digits of 27 is divisible by 3, so 3 is a factor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "27 divided by 3 is 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 is divisible by 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 divided by 3 is 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the prime factorization of 81 is 3 times 3 times 3 times 3 times 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you are taking a cube root, group like factors in threes. You have one group of three 3s. Take three 3s out of the radical and leave one factor of 3 outside of the radical. One factor of 3 remains under the radical.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |