document.write( "Question 433161: please help me solve this problem: Ivanna can jog to work in 3/4 of an hour. When she rides her bike, it takes her 1/3 of an hour. If she rides miles 9 per hour faster than she jogs, how far away is her work? \n" ); document.write( "
Algebra.Com's Answer #300275 by katealdridge(100)\"\" \"About 
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I hate problems like this.
\n" ); document.write( "Okay, d=rt (distance = rate*time)
\n" ); document.write( "let \"r%5B1%5D\"=the rate of jogging to work
\n" ); document.write( "let \"r%5B2%5D\"=the rate of biking to work
\n" ); document.write( "so \"d=r%5B1%5D%2A%283%2F4%29\" is the rate equation for jogging to work
\n" ); document.write( "and \"d=r%5B2%5D%2A%281%2F3%29\" is the rate equation for biking to work
\n" ); document.write( "d is the same for both equations because there is only 1 distance to work.
\n" ); document.write( "But they also tell you that she rides 9 miles/hr faster than she jogs. This means: \"r%5B2%5D=r%5B1%5D%2B9\"
\n" ); document.write( "So you can now take the biking equation and substitute \"r%5B1%5D%2B9\" in for \"r%5B2%5D\"
\n" ); document.write( "\"d=%28r%5B1%5D%2B9%29%2A%281%2F3%29\" the new biking equation
\n" ); document.write( "Now take both equations, the new biking and the jogging, and set them equal to each other:
\n" ); document.write( "\"r%5B1%5D%2A%283%2F4%29=%28r%5B1%5D%2B9%29%2A%281%2F3%29\" Now solve for \"r%5B1%5D\"
\n" ); document.write( "\"%283%2F4%29r%5B1%5D=%281%2F3%29%28r%5B1%5D%2B9%29\" Simplifying a little
\n" ); document.write( "\"%283%2F4%29r%5B1%5D=%281%2F3%29r%5B1%5D%2B3\" distributing the \"1%2F3\"
\n" ); document.write( "\"%285%2F12%29r%5B1%5D=3\" subtracting \"%281%2F3%29r%5B1%5D\" from both sides.
\n" ); document.write( "\"r%5B1%5D=7.2\" multiplying both sides by \"12%2F5\"
\n" ); document.write( "This means the rate of jogging to work is 7.2 miles/hour (sounds more like sprinting to me)
\n" ); document.write( "Now that you've got that done, you can find out the distance.
\n" ); document.write( "\"d=r%5B1%5D%2A%283%2F4%29\" plug in 7.2 for \"r%5B1%5D\"
\n" ); document.write( "\"d=7.2%2A%283%2F4%29\"
\n" ); document.write( "\"d=5.4miles\"\r
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