document.write( "Question 433161: please help me solve this problem: Ivanna can jog to work in 3/4 of an hour. When she rides her bike, it takes her 1/3 of an hour. If she rides miles 9 per hour faster than she jogs, how far away is her work? \n" ); document.write( "
Algebra.Com's Answer #300275 by katealdridge(100)![]() ![]() You can put this solution on YOUR website! I hate problems like this. \n" ); document.write( "Okay, d=rt (distance = rate*time) \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "so \n" ); document.write( "and \n" ); document.write( "d is the same for both equations because there is only 1 distance to work. \n" ); document.write( "But they also tell you that she rides 9 miles/hr faster than she jogs. This means: \n" ); document.write( "So you can now take the biking equation and substitute \n" ); document.write( " \n" ); document.write( "Now take both equations, the new biking and the jogging, and set them equal to each other: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This means the rate of jogging to work is 7.2 miles/hour (sounds more like sprinting to me) \n" ); document.write( "Now that you've got that done, you can find out the distance. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |