document.write( "Question 433161: please help me solve this problem: Ivanna can jog to work in 3/4 of an hour. When she rides her bike, it takes her 1/3 of an hour. If she rides miles 9 per hour faster than she jogs, how far away is her work? \n" ); document.write( "
Algebra.Com's Answer #300268 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Ivanna can jog to work in 3/4 of an hour. When she rides her bike, it takes her 1/3 of an hour. If she rides miles 9 per hour faster than she jogs, how far away is her work?
\n" ); document.write( "------------
\n" ); document.write( "Jogging DATA:
\n" ); document.write( "time = 3/4 hr; rate = x mph ; distance = rt = (3/4)x miles
\n" ); document.write( "--------------
\n" ); document.write( "Riding DATA:
\n" ); document.write( "time = 1/3 hr; rate = x+9 mph ; distance = rt = (1/3)(x+9) miles
\n" ); document.write( "-------------------
\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "(3/4)x = (1/3)(x+9)
\n" ); document.write( "Multiply both sides by 12 to get:
\n" ); document.write( "9x = 4x+36
\n" ); document.write( "5x = 36
\n" ); document.write( "x = 36/5 = 7 1/5 miles (distance to work)
\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=========== \n" ); document.write( "
\n" );