document.write( "Question 433138: The perimeter of a rectangle is 268 inches. The length exceeds the width by 64 inches. Find the length and width \n" ); document.write( "

Algebra.Com's Answer #300248 by katealdridge(100) $\"\"$ $\"About$

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Perimeter of rectangle=2L+2W=268
\n" ); document.write( "L=W+64
\n" ); document.write( "Substitute W+64 in for L in the perimeter equation
\n" ); document.write( " $\"2%28W%2B64%29%2B2W=268\"$ Simplify and solve
\n" ); document.write( " $\"2W%2B128%2B2W=268\"$
\n" ); document.write( " $\"4W%2B128=268\"$
\n" ); document.write( " $\"4W=140\"$
\n" ); document.write( " $\"W=35\"$
\n" ); document.write( "Since the length exceeds the width by 64, $\"L=35%2B64=99\"$ \n" ); document.write( "

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