document.write( "Question 433137: what is the equatio for a line perpendicular to 3x+4y=12 and passes through (7,1)?\r
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Algebra.Com's Answer #300236 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
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document.write( "  where m is the slope and b the y-intercept.  
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document.write( "perpendicular to 3x+4y=12 and passes through (7,1)?
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document.write( "3x+4y=12  y= (-3/4)x + 3 ( m = (-3/4))
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document.write( "NEw Line: Perpendicular Line will have slope that is the negative reciprocal,
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document.write( " y = (4/3)x + b   |Using ordered pair (7,1) to solve for b
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document.write( " 1 = (4/3)*7 + b  
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document.write( " -25/3 = b 
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document.write( "  y = (4/3)*x - 25/3
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