document.write( "Question 433133: Suppose you have 12 coins that total 32 cents. Some coins are nickels, while the rest are pennies. How many of each coin do you have?\r
\n" ); document.write( "\n" ); document.write( "Please show work and explain!\r
\n" ); document.write( "\n" ); document.write( "Thank you :)
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Algebra.Com's Answer #300228 by katealdridge(100)\"\" \"About 
You can put this solution on YOUR website!
This is a system of equations
\n" ); document.write( "One equation involves the number of coins:
\n" ); document.write( "n + p = 12
\n" ); document.write( "The involves the total value:
\n" ); document.write( ".05n + .01p = .32
\n" ); document.write( "Solve the first equation for either variable, we'll choose n.
\n" ); document.write( "\"n%2Bp=12\"
\n" ); document.write( "\"n=12-p\"
\n" ); document.write( "Then take 12-p and substitute it in for n in the second equation.
\n" ); document.write( "\".05%2812-p%29%2B.01p=.32\"
\n" ); document.write( "Then solve for p.
\n" ); document.write( "\".60-.05p%2B.01p=.32\"
\n" ); document.write( "\".60-.04p=.32\"
\n" ); document.write( "\"-.04p=-.28\"
\n" ); document.write( "\"p=7\" So there are 7 pennies. This leaves 5 nickels.
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