document.write( "Question 433056: Nielsen Media Research wants to estimate the mean amount of time(in minutes) that full-time college students spend watching television each weekday. find the sample size necessary to estimate that mean with a 15-min margin of error. Assume that a 96% confidence level is desired. Also assume that a pilot study showed that the standard deviation is estimated to be 112.2 minutes. \n" ); document.write( "

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Nielsen Media Research wants to estimate the mean amount of time(in minutes) that full-time college students spend watching television each weekday. find the sample size necessary to estimate that mean with a 15-min margin of error. Assume that a 96% confidence level is desired. Also assume that a pilot study showed that the standard deviation is estimated to be 112.2 minutes.
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\n" ); document.write( "Since ME = zs/sqrt(n)
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\n" ); document.write( "n = [zs/ME]^2
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\n" ); document.write( "n = [2.0537*112.2/15]^2
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\n" ); document.write( "n = 236 when rounded up
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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