document.write( "Question 433053: sqrt of y + 10 = y - 2\r
\n" ); document.write( "\n" ); document.write( "solve each radical equation. check your solution
\n" ); document.write( "

Algebra.Com's Answer #300167 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "\"sqrt%28y%2B10%29=+%28y-2%29\"
\n" ); document.write( " y + 10 = y^2-4y+4
\n" ); document.write( " y^2 -5y -6 = 0
\n" ); document.write( "factoring
\n" ); document.write( " (y-6)(y+1) = 0
\n" ); document.write( " Note:SUM of the outside terms(y) and the inside terms(-6y) = -5y
\n" ); document.write( " (y-6) = 0 \"+y+=highlight%28+6%29\"
\n" ); document.write( " (y+1) = 0 y = -1 |Extraneous, cannot use sqrt(9)≠ -3 \r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " \"sqrt%2816%29+=+6-2+=+4\"
\n" ); document.write( " \n" ); document.write( "
\n" );