document.write( "Question 433043: A canoeist can paddle a canoe 6 kilometers per hour in still water. If the canoeist can paddle 1 kilomter upstream in the same amount of time that they can paddle 1.5 kilometers downstream, how fast is the current? \n" ); document.write( "
Algebra.Com's Answer #300157 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let c represent the speed of the current
\n" ); document.write( "Question states*** time is the same Note: t = D/r
\n" ); document.write( "1.5/(6+c) = 1/(6-c) |cross Multiplying
\n" ); document.write( " 6 + c = 1.5(6-c)
\n" ); document.write( " 2.5c = 3
\n" ); document.write( " c = 1.2kmph\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 1.5/7.2 = 1/4.8 = .2083hr \r
\n" ); document.write( "\n" ); document.write( "As to Your further question:
\n" ); document.write( " A. \"%283%2F8x%29%2F%285%2F12x%29\" = (3/8x)(12x/5)= 36/40 = 9/10
\n" ); document.write( " B. 4/15y/12/5y = (4/15y)(5y/12) = 1/9
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