document.write( "Question 433005: The combined age of a father and son is 84.in 6 years time,the father will be twice as old as the son was three years ago.how old are they now? \n" ); document.write( "
Algebra.Com's Answer #300137 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! Let f = Father's age \n" ); document.write( "Let s = Son's age \n" ); document.write( "Given: \n" ); document.write( "f + s = 84 \n" ); document.write( "In 6 years' time, the father's age will be f+6. \n" ); document.write( "Three years ago, the son's age was s-3. \n" ); document.write( "So we can write the following equation: \n" ); document.write( "f + 6 = 2(s - 3) \n" ); document.write( "We have 2 equations and 2 unknowns. Solve for f in the 1st equation and put in the 2nd: \n" ); document.write( "(84-s) + 6 = 2s - 6 \n" ); document.write( "Solve for s: \n" ); document.write( "96 = 3s -> s = 32 \n" ); document.write( "So, the son is 32 yrs old and the father is 52 yrs old. \n" ); document.write( " \n" ); document.write( " |