document.write( "Question 432922: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3. \n" ); document.write( "
Algebra.Com's Answer #300122 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
We know that two lines are perpendicular when the product of their slopes is -1.\r
\n" ); document.write( "\n" ); document.write( "First we write 4x+2y=3 in the slope-intercept form:\"y=-2x%2B3%2F2\", we see that \r
\n" ); document.write( "\n" ); document.write( "the slope of this line is m1=-2. Let's the slope of the perpendicular line, m2, \r
\n" ); document.write( "\n" ); document.write( "then m1*m2=-1, substitute m1=-2, (-2)*m2=-1 => m2=1/2.\r
\n" ); document.write( "\n" ); document.write( "Now we find the equation of line through the point (-1, 6) with slope m2=1/2:\r
\n" ); document.write( "\n" ); document.write( "\"y-6=%281%2F2%29%2A%28x%2B1%29\", write it in the slope-intercept form.\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29%2Ax%2B7\", and in the standard form:\r
\n" ); document.write( "\n" ); document.write( "\"x-2y=-14\"\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C+300%2C+-15%2C+5%2C+-5%2C+10%2C+-2x%2B%283%2F2%29%2C+%281%2F2%29x%2B7%29\"\r
\n" ); document.write( "\n" ); document.write( "Done.
\n" ); document.write( "
\n" );