document.write( "Question 432922: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3. \n" ); document.write( "
Algebra.Com's Answer #300122 by Gogonati(855)![]() ![]() You can put this solution on YOUR website! We know that two lines are perpendicular when the product of their slopes is -1.\r \n" ); document.write( "\n" ); document.write( "First we write 4x+2y=3 in the slope-intercept form: \n" ); document.write( "\n" ); document.write( "the slope of this line is m1=-2. Let's the slope of the perpendicular line, m2, \r \n" ); document.write( "\n" ); document.write( "then m1*m2=-1, substitute m1=-2, (-2)*m2=-1 => m2=1/2.\r \n" ); document.write( "\n" ); document.write( "Now we find the equation of line through the point (-1, 6) with slope m2=1/2:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Done. \n" ); document.write( " |