document.write( "Question 45203This question is from textbook College Algebra
\n" ); document.write( ": Find the maximum or minimum value of the function\r
\n" ); document.write( "\n" ); document.write( "f(t)= 10t^2 + 40t + 113\r
\n" ); document.write( "\n" ); document.write( "t = -40/(2*10) = -40/20 = -2 minimum\r
\n" ); document.write( "\n" ); document.write( "10(t^2 + 4t) + 113
\n" ); document.write( "10(t^2 + 4t +4) + 113 - 40
\n" ); document.write( "10(t + 2)^2 + 73
\n" ); document.write( "y = 73\r
\n" ); document.write( "\n" ); document.write( "Thank you very much again! \n" ); document.write( "

Algebra.Com's Answer #30012 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
This is correct, except that as long as you found the max/min at $\"t=-b%2F%282a%29=+-2\"$ , you could have found the minimum value by just substituting this value of t into the original equation: \r
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\n" ); document.write( "\n" ); document.write( "Minimum value = $\"f%28-2%29+=+10%28-2%29%5E2%2B40%2A%28-2%29+%2B113\"$ \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "

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