document.write( "Question 44967: 2x-3y+z=7
\n" ); document.write( "x+2y-3z=7
\n" ); document.write( "-x+4y+3z=5\r
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\n" ); document.write( "\n" ); document.write( "solve in three variables using cramer's rule\r
\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #30011 by checkley71(8403)\"\" \"About 
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2 -3 1 |
\n" ); document.write( "1 2 -3 | =2(6+12)+3(3-3)+(4+2)=36+0+6=42
\n" ); document.write( "-1 4 3 |\r
\n" ); document.write( "\n" ); document.write( "7 -3 1 |
\n" ); document.write( "7 2 -3 |=7(6+12)+3(21+15)+28-10)=126+108+18=252
\n" ); document.write( "5 4 3 |\r
\n" ); document.write( "\n" ); document.write( "2 7 1 |
\n" ); document.write( "1 7 -3 |=2(21+15)-7(3-3)+(5=7)=72+0+12=84
\n" ); document.write( "-1 5 3 |\r
\n" ); document.write( "\n" ); document.write( "2 -3 7 |
\n" ); document.write( "1 2 7 |=2(10-28)+3(5+7)+7(4+2)=-36+36+42=42
\n" ); document.write( "-1 4 5 |\r
\n" ); document.write( "\n" ); document.write( "THUS THE FOLLOWING SOLUTIONS:\r
\n" ); document.write( "\n" ); document.write( "X=252/42 OR X=6
\n" ); document.write( "Y=84/42 OR Y=2
\n" ); document.write( "Z=42/42 OR Z=1
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