document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432975>Question 432975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jamie drove to visit her parents who live 600 miles away on her waY THERe her average speed was 20 mph faster than on her way home. if jamie spent a total of 25 hours driving find the two rates </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300105 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Jamie's speed be x.  Her speed on the way home was x+20.  Thus:<BR>\n" );
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document.write( "600/x+600/(x+20)=25<BR>\n" );
document.write( "Multiply each side by (x)(x+20):<BR>\n" );
document.write( "600(x+20)+600x=25(x2+20x)<BR>\n" );
document.write( "1200x+12000=25x2+500x<BR>\n" );
document.write( "0=25x2-700x-12000<BR>\n" );
document.write( "0=x2-28x-480<BR>\n" );
document.write( "0=(x+12)(x-40)<BR>\n" );
document.write( "x=-12,40<BR>\n" );
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document.write( "Throwing out the negative result, we get her speed going there to be 40mph, and 60mph to be her speed coming back. </SPAN>\n" );
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