document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432862>Question 432862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could you explain how to do these like one train leaves at 8 am at 30 mph and another at 9 am at 40mph when will they meet or pass each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300062 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A  	30	mph					<BR>\n" );
document.write( "Train B  	40	mph					<BR>\n" );
document.write( "							<BR>\n" );
document.write( "Train A passes station at 		08:00					<BR>\n" );
document.write( "Train B passes station at		09:00					<BR>\n" );
document.write( "							<BR>\n" );
document.write( "Difference in time=01:00  				<BR>\n" );
document.write( "Train Awill have covered 30 miles before Train B starts<BR>\n" );
document.write( "							<BR>\n" );
document.write( "catch up distance=		30	miles				<BR>\n" );
document.write( "catch up speed =		40	-30	mph			<BR>\n" );
document.write( "catch up speed =		10	mph				<BR>\n" );
document.write( "							<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed							<BR>\n" );
document.write( "catch up time=		30	/	10			<BR>\n" );
document.write( "catch up time=		3	hours				<BR>\n" );
document.write( "catch up time=		180	minutes				<BR>\n" );
document.write( "It will catch up at 	12:00:00 Noon			<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );