document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432385>Question 432385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem\r<BR>\n" );
document.write( "\n" );
document.write( "determine k so that the first polynomial is a factor of the second.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%2B2+ ALIGN=MIDDLE  ALT=\"+x%2B2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E3+%2B+3x%5E2+%2B+k+ ALIGN=MIDDLE  ALT=\"+2x%5E3+%2B+3x%5E2+%2B+k+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x-2+ ALIGN=MIDDLE  ALT=\"+x-2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E4+-+2x%5E3+%2Bkx%2B+6+ ALIGN=MIDDLE  ALT=\"+x%5E4+-+2x%5E3+%2Bkx%2B+6+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "I tried but I don't understand it still </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300037 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> determine k so that the first polynomial is a factor of the second.<BR>\n" );
document.write( " x+2; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E3+%2B+3x%5E2+%2B+k+ ALIGN=MIDDLE  ALT=\"+2x%5E3+%2B+3x%5E2+%2B+k+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Use synthetic division, we have to put a zero in the x position<BR>\n" );
document.write( ":<BR>\n" );
document.write( "_________________________<BR>\n" );
document.write( "-2|2 + 3 + 0 + k<BR>\n" );
document.write( "......... - 4 + 2 - 4<BR>\n" );
document.write( ".....---------------<BR>\n" );
document.write( "..... 2 - 1 + 2 + 0<BR>\n" );
document.write( "from this we have the equation <BR>\n" );
document.write( "k - 4 = 0<BR>\n" );
document.write( "k = 4<BR>\n" );
document.write( "Then the equation is: 2x^3 + 3x^2 + 4, which is :(x+2) (2x^2 - x + 2)<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( " x-2; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E4+-+2x%5E3+%2Bkx%2B+6+ ALIGN=MIDDLE  ALT=\"+x%5E4+-+2x%5E3+%2Bkx%2B+6+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "Use synthetic division, we have to put a zero in the x^2 position<BR>\n" );
document.write( ":<BR>\n" );
document.write( "_________________________<BR>\n" );
document.write( "+2|1 - 2 + 0 + k + 6<BR>\n" );
document.write( "......... +2 + 0 + 0 + 2k<BR>\n" );
document.write( ".....--------------------<BR>\n" );
document.write( "..... 1 + 0 + 0 + k  + 0<BR>\n" );
document.write( "from this we have the equation <BR>\n" );
document.write( "2k + 6 = 0<BR>\n" );
document.write( "2k = -6<BR>\n" );
document.write( "k = -3<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The equation: x^4 - 2x^3 - 3x + 6; which is (x-2)*(x^3 - 3x) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );