document.write( "Question 432763: Find the area of a rhombus that has one side of length 10 and diagonals that differ by 4.\r
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\n" ); document.write( "\n" ); document.write( " If log155= a, express log159 in terms of a. \n" ); document.write( "

Algebra.Com's Answer #300022 by Gogonati(855) $\"\"$ $\"About$

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Let's the smaller diagonal x cm, then the greater will be x+4 cm. As you know the rhombus diagonals are perpendicular and bisect each other.With these knowledges applying Pythagorean theorem we have:\r
\n" ); document.write( "\n" ); document.write( " $\"10%5E2-%28x%2B4%29%5E2%2F4=x%5E2%2F4\"$ , solving this equation we find the diagonals.\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B4x-392=0\"$ , one diagonal is D1=18cm and the other D2=18+4=22cm\r
\n" ); document.write( "\n" ); document.write( "As you know the area of rhombus is: $\"A=%281%2F2%29%2AD1%2AD2=%281%2F2%29%2A18%2A22=198cm%5E2\"$ \n" ); document.write( "

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