document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432741>Question 432741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If there is a committee of 15 people, how many ways is there to divide it into 3 subcommittees of 3 people, 5 people, and 7 people.\r<BR>\n" );
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document.write( "Since order does not matter, i have tried 15C3*15C5*15C7 I am not getting the given answer of 360360 though... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300007 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15C7*8C5*3C3=360,360 Once they are on the committee of 7 you only have 8 bodies remaining for the committee of 5 and then only 3 left for the committee of 3.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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