document.write( "Question 432653: Please help! Im stuck!\r
\n" ); document.write( "\n" ); document.write( "a scientist wants to estimate the age of a piece of wood. The half life of carbon-14 is 5730 years. Let f(t) represent the percent of carbon-14 that remains in the wood at the t years after the wood dies.\r
\n" ); document.write( "\n" ); document.write( "Equation:\r
\n" ); document.write( "\n" ); document.write( "f(t)= 100(1/2)^t/5730\r
\n" ); document.write( "\n" ); document.write( "If 20% of the carbon-14 remains, how old is the wood. \n" ); document.write( "

Algebra.Com's Answer #299964 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "f(t)= 100(1/2)^t/5730 
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document.write( "If 20% of the carbon-14 remains, how old is the wood.
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document.write( " .20 =(1/2)^t/5730 
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document.write( " log.2/log.5 = t/5730
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document.write( " 5730(log.2/log.5) = t
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document.write( " 5730*2.3219 = 12,304.648  years old\r
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document.write( "make sense: 25% left after 2*5730 = 11,460 years \n" );
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