document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432637>Question 432637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How does sec(cos^(-1) 1/2) equal to 2? I know that cos 1/2 is at 60 degrees and 300 degrees, where do I go from there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299963 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You do not even need to evaluate <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%5E%28-1%29+%281%2F2%29 ALIGN=MIDDLE  ALT=\"cos%5E%28-1%29+%281%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. The expression <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sec%28cos%5E%28-1%29%281%2F2%29%29 ALIGN=MIDDLE  ALT=\"sec%28cos%5E%28-1%29%281%2F2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is equivalent to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%28cos%28cos%5E%28-1%29%281%2F2%29%29%29 ALIGN=MIDDLE  ALT=\"1%2F%28cos%28cos%5E%28-1%29%281%2F2%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Since cosine and arccosine are inverse functions, the end result is the argument of the function, or 1/2. Hence, it is equal to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%281%2F2%29 ALIGN=MIDDLE  ALT=\"1%2F%281%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or 2. </SPAN>\n" );
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