document.write( "Question 432586: Investments: A total of $5000 is invested at 3% and 5% annual interest. After 1 year the total interest equals $210. How much money is invested at each interest rate? \n" ); document.write( "
Algebra.Com's Answer #299932 by jorel1380(3719)\"\" \"About 
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The total of the investments is $5000, thus x+y=5000:
\n" ); document.write( "x+y=5000
\n" ); document.write( ".03x+.05y=210
\n" ); document.write( "Multiply the second equation by 100--
\n" ); document.write( "3x+5y=21000
\n" ); document.write( "5x+5y=25000
\n" ); document.write( "-----------
\n" ); document.write( "2x=4000
\n" ); document.write( "x=2000
\n" ); document.write( "y=3000
\n" ); document.write( "=============
\n" ); document.write( "$2000 was invested at 3%, 3000 was invested at 5%.
\n" ); document.write( "
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