document.write( "Question 432586: Investments: A total of $5000 is invested at 3% and 5% annual interest. After 1 year the total interest equals $210. How much money is invested at each interest rate? \n" ); document.write( "
Algebra.Com's Answer #299932 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! The total of the investments is $5000, thus x+y=5000: \n" ); document.write( "x+y=5000 \n" ); document.write( ".03x+.05y=210 \n" ); document.write( "Multiply the second equation by 100-- \n" ); document.write( "3x+5y=21000 \n" ); document.write( "5x+5y=25000 \n" ); document.write( "----------- \n" ); document.write( "2x=4000 \n" ); document.write( "x=2000 \n" ); document.write( "y=3000 \n" ); document.write( "============= \n" ); document.write( "$2000 was invested at 3%, 3000 was invested at 5%. \n" ); document.write( " |