document.write( "Question 432553: One more for verification purposes:\r
\n" ); document.write( "\n" ); document.write( "IF something increases by 40% every 6 months what is the 1-year % increase?\r
\n" ); document.write( "\n" ); document.write( "Let S= something\r
\n" ); document.write( "\n" ); document.write( "S=(1+.40)^12 = S(1.40)^12 = S(56.59) = S increased by 56.59% in 1 year.\r
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Algebra.Com's Answer #299917 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "IF something increases by 40% every 6 months what is the 1-year % increase
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document.write( "After 1st 6mos, S would be S + .40S OR 1.40S
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document.write( "after 2nd 6mos. S would be [(1.40S) + .40*(1.40S)] OR 1.96S or a 96% increase.
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