document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432501>Question 432501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of pure baking soda must be added to 180 liters of a 40% baking soda solution to get a 70% baking soda solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299909 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The initial amount of baking soda in the 40% solution = 0.40*180 = 72 liters<BR>\n" );
document.write( "Let x = the number of liters of baking soda to add<BR>\n" );
document.write( "For a 70% solution we have<BR>\n" );
document.write( "0.70 = (72+x)/(180+x) <BR>\n" );
document.write( "since the same amount, x, is added to the solution and the original amount of baking soda<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "0.7(180+x) = 72+x<BR>\n" );
document.write( "126 + 0.7x = 72 + x -> 0.3x = 72 -> x = 180 liters<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "(72+180)/(180+180) = 252/360 = 0.7<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );