document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432486>Question 432486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36 ft. The length is 2 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width.\r<BR>\n" );
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document.write( "I am no good at graphing can someone help please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299856 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is x + y + x + y = 2(x + y) = 36 ……………………………(1)\r<BR>\n" );
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document.write( "We know that x = y + 2 so substituting this for x in (1) we have\r<BR>\n" );
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document.write( "2(y + 2 + y) = 36 …………………………………………………………………………(2)\r<BR>\n" );
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document.write( "Rearranging (2) we have 4y + 4 = 36 or 4y = 32 giving y = 8\r<BR>\n" );
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document.write( "So if the width is 8 ft and the length is 8 ft + 2 ft = 10 ft, we have a rectangle with a length 10 ft and a width 8 ft.\r<BR>\n" );
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document.write( "Go all the way round and you have 10 ft + 8 ft + 10 ft + 8 ft = 36 ft </SPAN>\n" );
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