document.write( "Question 432456: A passenger train traveling at 90mph leaves Amarillo, Texas 1 hour after a freight train. When will the passenger train pass the freight train which is traveling at 75mph? \n" ); document.write( "
Algebra.Com's Answer #299851 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x and (x+1)represent the times 90mph & 75mph train travel before they meet
\n" ); document.write( "Note: D = r*t and distance traveled the same by both trains
\n" ); document.write( " 90x = 75(x+1)
\n" ); document.write( " 15x = 75
\n" ); document.write( " x = 5hr, time 90mph(passenger train) travels before they meet \r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 90mph*5hr = 75mph*6hr = 450mi \n" ); document.write( "
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