document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432404>Question 432404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Karen walsh has twice as much money invested at 5% simple annual interest as she does at 4%. if her yearly income from these two investments is $350, how much does she have invested at each interest rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299815 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Part I	4.00%	per annum-------------	x			<BR>\n" );
document.write( "Part II	5.00%	per annum------------y=	2x	<BR>\n" );
document.write( "Interest-----	$350.00							<BR>\n" );
document.write( "									<BR>\n" );
document.write( "4.00%	x	+	5.00%	*	2	x	=	$350.00	<BR>\n" );
document.write( "0.04	x	+	0.05	*	2	x	=	$350.00	<BR>\n" );
document.write( "0.04	x	+	0.1	x	=	$350.00			<BR>\n" );
document.write( "0.14	x	=	$350.00						<BR>\n" );
document.write( "/	0.14								<BR>\n" );
document.write( "x=	$2,500.00	---	Part I						<BR>\n" );
document.write( "2x	=	$5,000.00		Part II				<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );