document.write( "Question 432425: The current in a stream moves at 8mph. A boat travels 19 miles upstream and 19 miles downstream in a total time of 9 hours. What is the speed of the boat in still water?\r
\n" ); document.write( "\n" ); document.write( "All I've been able to come up with is that if it took 9 hours to go 38 miles the boat would be going an average of 4.222mph.
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Algebra.Com's Answer #299813 by mananth(16946)\"\" \"About 
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Boat speed x
\n" ); document.write( "current speed 8
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\n" ); document.write( "against current x-8 mph
\n" ); document.write( "with current x+8 mph
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\n" ); document.write( "Distance= 19 miles
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\n" ); document.write( "Time against + time with wind = 9 hours
\n" ); document.write( "t=d/r
\n" ); document.write( "...
\n" ); document.write( "19/(x + 8)+19/(x-8)=9
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\n" ); document.write( "LCD =(x-8)(x+8)
\n" ); document.write( "19*(x - 8)+19x+ 8)=9
\n" ); document.write( "19x-152+19x+152 =9(x ^2 -64)
\n" ); document.write( "38x=9x ^2-576
\n" ); document.write( "9x ^2-38x-576=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= 9 b= -38 c= -576
\n" ); document.write( "b^2-4ac= 1444 + 20736
\n" ); document.write( "b^2-4ac= 22180 :sqrt(22180)=148.93
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=(38+148.93)/18
\n" ); document.write( "x1=10.38 mph
\n" ); document.write( "x2=(38 -148.93 ) / 18
\n" ); document.write( "x2= -6.16 ( ignore negative)
\n" ); document.write( "speed = 10.38 mph
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