document.write( "Question 432425: The current in a stream moves at 8mph. A boat travels 19 miles upstream and 19 miles downstream in a total time of 9 hours. What is the speed of the boat in still water?\r
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document.write( "All I've been able to come up with is that if it took 9 hours to go 38 miles the boat would be going an average of 4.222mph.
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Algebra.Com's Answer #299813 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed x \n" ); document.write( "current speed 8 \n" ); document.write( " \n" ); document.write( "against current x-8 mph \n" ); document.write( "with current x+8 mph \n" ); document.write( " \n" ); document.write( "Distance= 19 miles \n" ); document.write( " \n" ); document.write( "Time against + time with wind = 9 hours \n" ); document.write( "t=d/r \n" ); document.write( "... \n" ); document.write( "19/(x + 8)+19/(x-8)=9 \n" ); document.write( " \n" ); document.write( "LCD =(x-8)(x+8) \n" ); document.write( "19*(x - 8)+19x+ 8)=9 \n" ); document.write( "19x-152+19x+152 =9(x ^2 -64) \n" ); document.write( "38x=9x ^2-576 \n" ); document.write( "9x ^2-38x-576=0 \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( "a= 9 b= -38 c= -576 \n" ); document.write( "b^2-4ac= 1444 + 20736 \n" ); document.write( "b^2-4ac= 22180 :sqrt(22180)=148.93 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=(38+148.93)/18 \n" ); document.write( "x1=10.38 mph \n" ); document.write( "x2=(38 -148.93 ) / 18 \n" ); document.write( "x2= -6.16 ( ignore negative) \n" ); document.write( "speed = 10.38 mph \n" ); document.write( " \n" ); document.write( " |