document.write( "Question 432354: Abigail is 4 times as old as Bonnie. In 6 years, Bonnie will be twice as old as Candice. If, 4 years from now, Abigail will be 36 years old, how old will Candice be in 6 years?\r
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document.write( "When i was setting an equation for Candice i thought it was 2(B+6) because Bonnie will be twice (2) as old as Candice (b+6), but in the answer key it's (b+6)/2. Can you please explain the whole problem to me ? Thank You \n" );
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Algebra.Com's Answer #299796 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Abigail is 4 times as old as Bonnie. In 6 years, Bonnie will be twice as old as Candice. If, 4 years from now, Abigail will be 36 years old, how old will Candice be in 6 years? \n" ); document.write( "In 4 years Abigail will be 36 years. \n" ); document.write( "So Abigail is 32 years now.\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "let candice age be x now. \n" ); document.write( "after 6 years \n" ); document.write( "she will be x+6 years. \n" ); document.write( "Bonnie will be 2(x+6) years \n" ); document.write( "... \n" ); document.write( "Bonnie's age now will be 2(x+6)-6 \n" ); document.write( "4 times Bonnies age = Abigail's age now \n" ); document.write( "4(2(x+6)-6)=32 \n" ); document.write( "4(2x+6)=32 \n" ); document.write( "8x+24=32 \n" ); document.write( "8x=32-24 \n" ); document.write( "8x=8 \n" ); document.write( "x= 1 Candice's age now\r \n" ); document.write( "\n" ); document.write( "After 6 years years she will be 6+1=7 years \n" ); document.write( " \n" ); document.write( " |