document.write( "Question 432362: 8+3x>2
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document.write( "how do i write the solution as an inquality ? \n" );
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Algebra.Com's Answer #299793 by rapaljer(4671) You can put this solution on YOUR website! 8+3x>2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 8 from each side:\r \n" ); document.write( "\n" ); document.write( "8-8+3x>2-8 \n" ); document.write( "3x>-6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I have a complete explanation on this topic on my website. To find my website click on my tutor name \"rapaljer\" anywhere in algebra.com. There you will find a link to take you to my website. On the Homepage of my website, look for the link near the top of the page \"Basic, Intermediate, and College Algebra: One Step at a Time.\" Next, click on \"Basic Algebra\", then look in Chapter 1, and click on Section 1.11 Inequalities. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( "Seminole State College of Florida \n" ); document.write( " |