document.write( "Question 432193: This is the equation:\r
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document.write( "((( (2 over x+3) + (1 over x) = (4 over 3x) )))\r
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document.write( "When I say over, I mean it is a fraction.\r
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document.write( "So far I've tried multiplying the whole thing by 3x, but its not right. Help? \n" );
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Algebra.Com's Answer #299743 by sudhanshu_kmr(1152) You can put this solution on YOUR website! \n" ); document.write( "2/(x+3) + 1/x = 4/3x\r \n" ); document.write( "\n" ); document.write( "=> 2/(x+3) = 4/3x - 1/x\r \n" ); document.write( "\n" ); document.write( "=> 2/(x+3) = [4 - 3]/3x\r \n" ); document.write( "\n" ); document.write( "=> 2/(x+3) = 1/3x\r \n" ); document.write( "\n" ); document.write( "=> 6x = x+3\r \n" ); document.write( "\n" ); document.write( "=> 5x = 3\r \n" ); document.write( "\n" ); document.write( "=> x = 3/5 \r \n" ); document.write( "\n" ); document.write( "so, x = 3/5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |