document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45171>Question 45171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for y. write the equation in the form y = mx + b.\r<BR>\n" );
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document.write( "3x + 2y = 6\r<BR>\n" );
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document.write( "I've been really having a tough time understanding this whole graph and linear equation thing. your help would be much appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29974 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for y. write the equation in the form y = mx + b.<BR>\n" );
document.write( "3x + 2y = 6<BR>\n" );
document.write( "2Y=-3X+6<BR>\n" );
document.write( "Y=-3X/2+6/2=-1.5X+3<BR>\n" );
document.write( "HENCE M=-1.5 AND C=3<BR>\n" );
document.write( "I've been really having a tough time understanding this whole graph and linear equation thing. your help would be much appreciated. </SPAN>\n" );
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