document.write( "Question 432174: Please help me solve this problem!!\r
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document.write( "The sume of the ages of 2 boys is 18. If 4 times the younger boys age is subtracted from 3 times the older boys age, the difference is 12. What are the ages of the two boys?\r
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document.write( "Please tell me how to solve this! \r
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document.write( "I have tried 2x=18 for the first equation
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document.write( "and then 3x-4x=12?
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document.write( "I am so lost\r
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document.write( "Please get back to me asap\r
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document.write( "I have class in an hour and a half!! \r
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document.write( "HELP!! \n" );
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Algebra.Com's Answer #299729 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let age of younger boy =x\r \n" ); document.write( "\n" ); document.write( "age of older boy = y\r \n" ); document.write( "\n" ); document.write( "x+y = 18 ..........(1)\r \n" ); document.write( "\n" ); document.write( "and 3y - 4x = 12 .........(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply equation 1 by 4 and add both equations\r \n" ); document.write( "\n" ); document.write( "4x + 4y = 72\r \n" ); document.write( "\n" ); document.write( "3y - 4x= 12\r \n" ); document.write( "\n" ); document.write( "then 7y = 84 \r \n" ); document.write( "\n" ); document.write( "=> y = 84/7 = 12\r \n" ); document.write( "\n" ); document.write( "x = 18 -12 = 6\r \n" ); document.write( "\n" ); document.write( "age of younger boy is 6, age of older boy is 12.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |