document.write( "Question 432148: log(x-5)= log(x-2)+1 \n" ); document.write( "
Algebra.Com's Answer #299719 by Alan3354(69443)\"\" \"About 
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log(x-5)= log(x-2)+1
\n" ); document.write( "log(x-5)= log(x-2) + log(10)
\n" ); document.write( "log(x-5)= log((x-2)*10)
\n" ); document.write( "x-5 = (x-2)*10
\n" ); document.write( "x-5 = 10x - 20
\n" ); document.write( "9x = 15
\n" ); document.write( "x = 5/3
\n" ); document.write( "----------
\n" ); document.write( "x = 5/3 causes logs of negative numbers, tho.
\n" ); document.write( "--> no solution\r
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