document.write( "Question 45154: Factor completely. b^2 – ab – 6a^2 \n" ); document.write( "
Algebra.Com's Answer #29971 by Earlsdon(6294)\"\" \"About 
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Factor:
\n" ); document.write( "\"b%5E2-ab-6a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "The factors of b^2 are (b)(b)
\n" ); document.write( "Tha factors of -6a^2 are (-a)(6a) or (2a)(-3a) or the same factors with their signs switched.\r
\n" ); document.write( "\n" ); document.write( "Now, how to get the coefficient of the middle term (-1) of your expression from this set of factors. The obvious choice is: (2)+(-3)\r
\n" ); document.write( "\n" ); document.write( "The factors are:
\n" ); document.write( "\"b%5E2-ab-6a%5E2+=+%28b%2B2a%29%28b-3a%29\"
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