document.write( "Question 45168: The lenght of a rectangle is 2 in. more than twice its width.if the perimeter of the rectangle is 34 in. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #29969 by aaaaaaaa(138)![]() ![]() ![]() You can put this solution on YOUR website! Some variables I'll use:\r \n" ); document.write( "\n" ); document.write( "l = length \n" ); document.write( "w = width \n" ); document.write( "p = perimeter\r \n" ); document.write( "\n" ); document.write( "First, we have that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And the formula for a perimeter calculation, in general, is l+l+w+w, or: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting 34 for p: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting 2w + 2 for l: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And now we solve for the width: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If l is 2w+2, substituting w for 5 gives us:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the length is 12 inches and the width, 5 inches. \n" ); document.write( " |