document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432043>Question 432043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?\r<BR>\n" );
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document.write( "2) Is there a formula to solve these types of problems? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299681 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)If Steven can mix 20 drinks in 5 minutes, then he mixes 4 drinks per minute. Sue mixes 2 drinks per minute, and Jack mixes 4/3 drink per minute. Thus they can mix:\r<BR>\n" );
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document.write( "4+2+4/3=12+6+4/3=22/3 drinks per minute\r<BR>\n" );
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document.write( "To pour 20 drinks they need 20/22/3 minutes, or 60/22 or 30/11 minutes.\r<BR>\n" );
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document.write( "2)A formula might be Total Work/Cumulative work per unit equals time. </SPAN>\n" );
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