document.write( "Question 431702: Find the polynomial P(x) of lowest degree that has the zeros, 5,-5,1,-1.
\n" ); document.write( "Answer: I know I have to set everything to 0.
\n" ); document.write( "x-5=0
\n" ); document.write( "x+5=0
\n" ); document.write( "x-1=0
\n" ); document.write( "x+1=0\r
\n" ); document.write( "\n" ); document.write( "(x-5)(x+5)(x-1)(x+1)=0
\n" ); document.write( "Now from there I don't know how to continue.
\n" ); document.write( "

Algebra.Com's Answer #299663 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
(x-5)(x+5)(x-1)(x+1)=0
\n" ); document.write( "is mostly right. It should be:
\n" ); document.write( "P(x) = (x-5)(x+5)(x-1)(x+1)

\n" ); document.write( "All that is left is to multiply out the right side. I'd suggest mulitplying the first two factors and the last two factors first. For these we can use the \"%28a%2Bb%29%28a-b%29+=+a%5E2-b%5E2\" pattern to multiply quickly:
\n" ); document.write( "\"P%28x%29+=+%28x%5E2+-+5%5E2%29%28x%5E2+-+1%5E2%29\"
\n" ); document.write( "or
\n" ); document.write( "\"P%28x%29+=+%28x%5E2+-+25%29%28x%5E2+-+1%29\"
\n" ); document.write( "Now just use FOIL to multiply the remaining factors.
\n" ); document.write( "
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