document.write( "Question 431927: You have 200 feet of fencing material to make a pen for live stock. If you make a rectangular pen, what is the maximum aree you can fence in? \r
\n" ); document.write( "\n" ); document.write( "Extend the table to determine the anser.\r
\n" ); document.write( "\n" ); document.write( "Base=3 Permimeter=200 Height=? Area=?
\n" ); document.write( "Base=20 Perimeter= 200 Height=? Area=?
\n" ); document.write( "I need help finding out the height and Area.
\n" ); document.write( "Help me Please & Thank you (:
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Algebra.Com's Answer #299648 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of the pen is 2l + 2w
\n" ); document.write( "The area of the pen is l*w
\n" ); document.write( "Given: 200 feet of material
\n" ); document.write( "So we can write
\n" ); document.write( "200 = 2l + 2w -> l + w = 100 -> l = 100 - w
\n" ); document.write( "Substitute this value for l in the equation for the area:
\n" ); document.write( "A = w(100-w)
\n" ); document.write( "This area will be maximized for dA/dw = 0
\n" ); document.write( "dA/dw = 100 - 2w
\n" ); document.write( "Set=0 and solve for w:
\n" ); document.write( "2w = 100 -> w = 50
\n" ); document.write( "So the length is also 50.
\n" ); document.write( "Therefore, the maximum area = 50*50 = 2500 sq. ft.
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