document.write( "Question 431949: SOLVE BY SUBSTITUTION METHOD :)\r
\n" ); document.write( "\n" ); document.write( "x+4=-1/2+4x
\n" ); document.write( "2x+3y=1/2x+2y+1\r
\n" ); document.write( "\n" ); document.write( "solve by ADDITION METHOD :)\r
\n" ); document.write( "\n" ); document.write( "3Y-1 divided by 2= 3x+8 divided by 5
\n" ); document.write( "x+y divided by 2= 6+x-y divided by 2
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Algebra.Com's Answer #299633 by anshu_a(16)\"\" \"About 
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SOLVE BY SUBSTITUTION METHOD :)\r
\n" ); document.write( "\n" ); document.write( "x+4=-1/2+4x\r
\n" ); document.write( "\n" ); document.write( "4+1/2 = 4x-x\r
\n" ); document.write( "\n" ); document.write( "9/2 = 3x or x= 3/2\r
\n" ); document.write( "\n" ); document.write( "SUBTITUTE VALUE OF x \r
\n" ); document.write( "\n" ); document.write( "2x+3y=1/2x+2y+1\r
\n" ); document.write( "\n" ); document.write( "2*3/2 + 3y = 1/(2*3\2)+2y+1\r
\n" ); document.write( "\n" ); document.write( "3+3y = 1/3+2y+1\r
\n" ); document.write( "\n" ); document.write( "3y-2y = 1/3+1-3\r
\n" ); document.write( "\n" ); document.write( "y = 1/3-2 = -5/3\r
\n" ); document.write( "\n" ); document.write( "solve by ADDITION METHOD :)\r
\n" ); document.write( "\n" ); document.write( "3Y-1 divided by 2= 3x+8 divided by 5
\n" ); document.write( "x+y divided by 2= 6+x-y divided by 2\r
\n" ); document.write( "\n" ); document.write( "(3y-1)/2 = (3x+8)/5\r
\n" ); document.write( "\n" ); document.write( "or 5(3y-1) = 2(3x+8)\r
\n" ); document.write( "\n" ); document.write( "15y-5 = 6x+16\r
\n" ); document.write( "\n" ); document.write( "or 6x-15y = -21------------(1)\r
\n" ); document.write( "\n" ); document.write( "(x+y)/2 = (6+x-y)/2 or (x+y) = (6+x-y)\r
\n" ); document.write( "\n" ); document.write( "2y = 6 or y = 3
\n" ); document.write( "put value of y in (1) and get x\r
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