document.write( "Question 431863: 1.Write in sigma notation:
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document.write( "0+3+8+15+24+35+48\r
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document.write( "2. Find the 10th term of the arithmetic sequence:
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document.write( "3/4, 13/12,17/12,..\r
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document.write( "3. Find the 6th term of the arithmetic sequence:
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document.write( "a-b, a, a+b,...\r
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document.write( "4. The common difference in an arithmetic sequence is 3. The 10th term is 23. Find the first term.\r
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document.write( "5. Insert 4 arithmetic means between 5 and 9. \n" );
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Algebra.Com's Answer #299621 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! 1. Looking at the terms of the series, we see that the n-th term is one less than n^2. For example, the 3rd term = 8 = 3^2 - 1 \n" ); document.write( "So, we can write the series as: \n" ); document.write( " \n" ); document.write( "2. The arithmetic sequence 3/4,13/12,17/12,... has a common difference of 1/3. \n" ); document.write( "So we can write: \n" ); document.write( "a_n = a_1 + (1/3)(n-1) \n" ); document.write( "Where a_1 is the first term of the sequence \n" ); document.write( "So the formula for the series becomes: \n" ); document.write( "a_n = 3/4 + n/3 - 1/3 -> a_n = 5/12 + n/3 \n" ); document.write( "So the 10th term in the sequence is a_10 = 5/12 + 10/3 = 5/12 + 40/12 = 45/12 \n" ); document.write( "3. The common difference is a-(a-b) = b \n" ); document.write( "So the formula for the series is: \n" ); document.write( "(a-b) + (n-1)b \n" ); document.write( "Putting in n=6 gives: \n" ); document.write( "(a-b) + 5b = a + 4b \n" ); document.write( "4. An arithmetic series is written a_n = a_1 + (n-1)d \n" ); document.write( "So we have a_n = a_1 + 3(n-1) \n" ); document.write( "For n=10, we have \n" ); document.write( "23 = a_1 + 3(9), or 23 = a_1 + 27 \n" ); document.write( "Therefore a_1 = -4 \n" ); document.write( " \n" ); document.write( " |