document.write( "Question 431877: An investor had a total of 25,000 put into a portfolio of stocks, bonds, and mutual funds. In one year, he earned 8% on the stock investment, 10% on the bond investment and 6% on the mutual funds investment. The annual(simple interest) return was $1860. if the amount invested in the mutual fund was twice the investment in bonds, then how much did he originally put in each of the three individual investments? \n" ); document.write( "
Algebra.Com's Answer #299597 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Bonds ------ $x -------10% \n" ); document.write( "Mutual funds -$2x-------6% \n" ); document.write( "Stock -------(25000-3x)---8%\r \n" ); document.write( "\n" ); document.write( "Interest = 1860\r \n" ); document.write( "\n" ); document.write( "10x+6*2x+8(25000-3x)= 1860*100\r \n" ); document.write( "\n" ); document.write( "10x+12x+200000-24x =186000 \n" ); document.write( "-2x=-14,000 \n" ); document.write( "x= $7000 ------- Bonds \n" ); document.write( "Mutual funds --- 2x= $14,000 \n" ); document.write( "Stocks --------- $4000\r \n" ); document.write( "\n" ); document.write( "CHECK\r \n" ); document.write( "\n" ); document.write( "7000*0.1+14000*0.06+4000*0.08=1860 \n" ); document.write( " |