document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431749>Question 431749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 5 times the width. the perimeter is 48 inches. find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299542 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"the length of a rectangle is 5 times the width. the perimeter is 48 inches. find the dimensions.\"\r<BR>\n" );
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document.write( "x = width<BR>\n" );
document.write( "5x = length {length is five times the width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2x + 2(5x) = 48 {perimeter is 2(width) + 2(length)}<BR>\n" );
document.write( "2x + 10x = 48 {multiplied through}<BR>\n" );
document.write( "12x = 48 {combined like terms}<BR>\n" );
document.write( "x = 4 {divided both sides by 12}<BR>\n" );
document.write( "5x = 20 {substituted 4, in for x, into 5x}\r<BR>\n" );
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document.write( "width = 4 in. and length = 20 in.<BR>\n" );
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