document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431672>Question 431672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the answer to 3 over 5-11i, in the form of a + bi?  I think I need to multiply 3 over 5-11i by 5+11i over 5+11i.  Can someone help me, please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299482 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you are correct, multiply 3/5-11i by 5+11i/5+11i, it's as good as multiplying it by 1 so we are not changing the number, expand the numerator, and then the denominator is just a constant that will spread over your numerator<BR>\n" );
document.write( "you should get (15+33i)/(25-121) </SPAN>\n" );
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