document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431626>Question 431626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is 1/36 a perfect square? Please explain why or why not? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299474 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if it is, you just need to find a number such that the number squared = 1/36\r<BR>\n" );
document.write( "\n" );
document.write( "let, a = (1/6), then a^2 = (1/6)^2 = (1^2/6^2)=(1/36)\r<BR>\n" );
document.write( "\n" );
document.write( "of course if you let b = -(1/6), you will get the same result, so yes, it is a perfect square, and we know this is true since we have found numbers a and b, such that a^2 and b^2 = (1/36)\r<BR>\n" );
document.write( "\n" );
document.write( "conversely if a number was not a perfect square, then if we try to take it's square root we will find it is not a rational number, and therefore not a perfect square </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );